Question

Please find answer for 8th question

Answer 1

$heya \\ \\ 4 {}^{k} - 4 {}^{k - 1} = 48 \\ \\ 4 {}^{k} - 4 {}^{k} \times 4 {}^{ - 1} = 48 \\ \\ put \: \: \: 4 {}^{k} = z \\ \\ \\ z - z \div 4 = 48 \\ \\ (4z - z) = 48 \times 4 \\ \\ 3z = (48 \times 4) \\ \\ 3z = 192 \\ \\ \\ z = 64 \\ \\ \\ \\ 4 {}^{k} = 64 \\ \\ 4 {}^{k} = 4 {}^{3} \\ \\ \\ k = 3$

Answer 2

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