Math, asked by hari171, 1 year ago

please find answer for this question

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Answered by RAJdba
0
let one unit be x
then the sides are 2x, 3x, 5x, 7x
a/q
2x+ 3x+5x +7x = 340m
17x = 340m
x = 340m / 17
x = 20m
therefore, sides are 40, 60, 100 ,140

% correct


plzz gv me brainliest
Answered by chhajedchirag1p32bb2
1
let x be the common multiple.
340 = 2x + 3x + 5x + 7x \\ 340 = 17x \\ x = \frac{340}{17} \\ x = 20
2x \\ 2 \times 20 = 40 \\ 3x \\ 3 \times 20 = 60 \\ 5x \\ 5 \times 20 = 100 \\ 7x \\ 7 \times 20 = 140

s = \frac{a + b + c + d}{2} \\ \frac{40 + 60 + 100 + 140}{2} \\ \frac{340}{2} \\ s = 170
 \sqrt{(s - a)(s - b)(s - c)(s - d)} \\ \sqrt{170 - 40 \times 170 - 60 \times 170 - 100 \times 170 - 140} \\ \sqrt{130 \times 110 \times 70 \times 30} \\ \sqrt{30030000} \\ 5479.96

area of cyclic quadrilateral is 5479.96 m^2
don't forget to do it brainliest

chhajedchirag1p32bb2: too much thank you for doing it brainliest.
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