Question

Please find answer please

Answer 1

$a+ \frac{1}{a} = \sqrt{3}$

Cube on both sides,
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by Formula $(a+b)^3 = a^3 + b^3 + 3ab(a+b)$
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$a^3 + \frac{1^3}{a^3} + 3[a* \frac{1}{a}] (a+ \frac{1}{a})$ = (√3)³

$a^3 + \frac{1}{a^3} + 3[ \sqrt{3} ] = 9$

$a^3 + \frac{1}{a^3} = 9-3 \sqrt{3}$

$a^3 + \frac{1}{a^3} = 3[3- \sqrt{3} ]$

i hope this will help you

-by ABHAY

Answer 2

Use this formula a plus b the whole cube equals to a cube plus b cube plus 3xaxbx a + b