Question

please find equivalent resistance ...​

Answer 1

.........................

Answer 2

Answer:

Req(AB) = 2 ohm

Explanation:

In loop AEF, 3 ohm + 3ohm = 6 ohm

1/R(AE) = 1/6 + 1/6 = 1/3

Req (AE) = 3 ohm

Similarly, in loop AED, 3ohm + 3 ohm = 6ohm

Req(AD) = 3 ohm

Similarly, in loop ADC, Req(AC) = 3 ohm

Hence, In Loop ABC, 3 ohm and 3 ohm are in series.

So, 3 + 3 = 6 ohm

6 ohm and 3 ohm ( across AB) are in parallel to each other.

So, 1/Req (AB) = 1 / 6 + 1/3 = 3/6

Req(AB) = 2 ohm