please find fdhxjcgNVdtyhio
Attachments:
Answers
Answered by
2
let the zero be x and 1/x.
x×1/x = 6k/(k²+k)
=>by cross multiplication,
=>k²+k = 6k
=>k²+k-6k = 0
=>k²-5k = 0
=>k(k-5) = 0
k = 0 or k = 5
x×1/x = 6k/(k²+k)
=>by cross multiplication,
=>k²+k = 6k
=>k²+k-6k = 0
=>k²-5k = 0
=>k(k-5) = 0
k = 0 or k = 5
gautamsama:
thanks vvvvvvvvvery much
Similar questions