Question

Please find find the solution ​

Answer 1

Answer:

here is your answer

please mark me as brainlist

Answer 2

$\sf\huge\bold{Answer:}$

$\fbox{Solution 3 }$

(a)

$\sf\purple{› \:Reaction\:of\:Fe\:with\:Oxygen}$

$\sf Fe + O_{2} → Fe_{2} O_{3}$

$\fbox{Balanced Equation :}$

$\sf Fe + 3O_{2} → Fe_{2} O_{3}$

$\sf\purple{› \:Reaction\:of\:Na\:with\:Oxygen}$

$\sf Na + O_{2} → Na_{2} O + Na _{2}O_{2}$

Major product is $\sf Na_{2}O$

$\fbox{Balanced Equation :}$

$\sf 4Na+O_{2}→2Na_{2} O.$

(b)

$\sf\purple{› \:Reaction\:of\:Mg\:with\:Water}$

$\sf Mg+H_{2} O→MgO + H_{2}$

$\sf\purple{› \:Reaction\:of\:Cu\:with\:Water}$

$\sf Cu+H_{2}O→ \red× (No \: reaction)$

• Copper lies below hydrogen in the activity series of metals, therefore it can not displace hydrogen from water which means it cannot react with water on strong heating.

(c)

$\sf\purple{› \:Reaction\:of\:Zn\:with\:HCl}$

$\sf \: Zn(s) + HCl(aq) → ZnCl_{2} (aq) + H_{2} (g)$

$\fbox{Balanced Equation :}$

$\sf \: Zn(s) + 2HCl(aq) → ZnCl_{2} (aq) + H_{2} (g)$

$\sf\purple{› \:Reaction\:of\:Cu\:with\:HCl}$

$\sf Cu+HCl \: → \red× (No \: reaction)$

Copper is present below hydrogen in the reactivity series. So, copper cannot replace the hydrogen in HCl to form $\sf \: CuCl_{2}$. Hence, when copper (Cu) reacts with hydrochloric acid (HCl) there will be no reaction.