Question

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Answer 1

Answer:

Explanation:

Orbital angular momentum=$\sqrt{l(l+1)}$ h/2π

For d electron l=2

So Orbital angular momentum=$\sqrt{2*3}$ h/2π

=$\sqrt{6}$ h/2π

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Answer 2

Explanation:

Orbital angular momentum=\sqrt{l(l+1)}l(l+1) h/2π

For d electron l=2

So Orbital angular momentum=\sqrt{2*3}2∗3 h/2π

=\sqrt{6}6 h/2π

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