Math, asked by Bunny2403, 8 months ago

Please find it out I love who will find it out

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Answers

Answered by Devamgangar
1

Answer:

the remaining sides are 15 and 20

Answered by Anonymous
1

Answer:

Perimeter of that triangle = 60cm

the measure of hypotaneous = 25cm

then the rest sides must measure = 60-25

= 35

let one side be x

then, thw measure of the third side must be 35 - x

using pythagoras theorem

(25)^2 =(x)^2 + (35-x)^2

625 = x^2 + x^2 - 70x + 1225

x^2 + x^2 - 70x + 1225 = 625

x^2 + x^2 - 70x + 1225 -625 = 0

2 x^2 - 70x + 600 = 0

2x^2 - 40x - 30 x + 600= 0

2x (x-20) -30 ( x - 20) = 0

(x-20)(2x-30)=0

x -20 = 0

x = 20

2x -30 =0

2x =30

x = 15

so,

one of the side measure either 20 cm 15 cm

if one side measure 20cm then the other must measure 35 -20 = 15cm

and if it measured 15 cm then the other side measure 35-15 = 20 cm

so,

we will get 20cm and 15 cm as our remaining sides.

one of then will be height and the other misy be the base,

now apply the formula of area of triangle i.e

(1/2) (height)(base)

= (1/2 )(20)(15)

= 150 cm^2

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