Question

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Answer 1

Question :-

Show that x = 3 and y = 2 is a solution of linear equation 2x + 3y = 12

Answer :-

Substitute the value of x and y in the equation :-

$\sf 2x + 3y = 12$

$\sf 2 ( 3 ) + 3 ( 2 ) = 12$

$\sf 6 + 6 = 12$

$\sf 12 = 12$

Question :-

Find rational number b/w 3 & 4.

Answer :-

To find a rational number between two number a and b -

$\sf = \frac{a+b}{2}$

Rational number b/w 3 & 4

$\sf = \frac{3 + 4}{2}$

$\sf = \frac{7}{2}$

Question :-

What is the degree of 7?

Answer :-

Degree is the highest power of the polynomial of x

$\sf 7 = 7 \times x^0$

So, the degree of 7 is 0.

Question :-

Factorize :- $\sf x^2 + 5x - 24$

Answer :-

By using splitting the middle term method :-

⇒ $\sf = x^2 + 8x - 3x - 24$

⇒ $\sf = x(x+8) - 3(x + 8)$

⇒ $\sf = (x-3)(x + 8)$

$\sf x^2 + 5x - 24 = (x-3)(x + 8)$

Question :-

Find the measure of angle which is 24° more than its complement.

Answer :-

Let the angle be x

Complementary angle = 90 - x

According to the question :-

⇒ $\sf x = 90 - x + 24$

⇒ $\sf x = 114 - x$

⇒ $\sf 2x = 114$

⇒ $\sf x = \frac{114}{2}$

⇒ $\sf x = 57$

Answer 2

Answer:

(21) put x = 3 and y = 3 in eq , we get

2×3+3×2=12 therefore LHS = RHS

(22) 3 ×7/7 = 21/7

4 × 7/7 = 28/7

one rational number between 3 and 4

22/7

(23) degree of 7 is 0

(24) put x-3 = 0

x = -3

now put p( x) = a

= a

(25) x^ 2 +5x-24

x^2+8x-3x-24

x( x+8)-3(x+8)

(x+8) (x-3)

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