CBSE BOARD X, asked by ishika7968, 1 year ago

Please find mode of this given table..
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Answered by manas1112
3

l=30 ,f1=10 f2=3 f0=9 h = 5

mode= l+ ( f1-f0 /2f1 - f0 -f2 ) ×h

= 30 +(10-9/20-9-3)×5

=30+ (1/8) 5

=30+(5/8)

=30+0.62

= 30.62


manas1112: This is right answer
ishika7968: Yup!!
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