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put x = 1 and then x = 0
at x= 1
2(1)³— 2(1)²— +a-b =0
so , we get a-b=0
now put x= 0
we get ,b=0
so , a=b = 0 ans.
at x= 1
2(1)³— 2(1)²— +a-b =0
so , we get a-b=0
now put x= 0
we get ,b=0
so , a=b = 0 ans.
Answered by
4
Given f(x) = 2x^3 - 2x^2 + ax - b.
Given that 0 and 1 are the zeroes of the polynomial.
Substitute x = 0:
f(0) = 0.
⇒ 2(0)^3 - 2(0)^2 + a(0) - b = 0
⇒ 0 - 0 + 0 - b = 0
⇒ b = 0.
Substitute x = 1:
f(1) = 0
⇒ 2(1)^3 - 2(1)^2 + a(1) - b = 0
⇒ 2 - 2 + a - b = 0
⇒ a - b = 0
⇒ a - 0 = 0
⇒ a = 0.
Therefore, the value of a = 0 and b = 0.
Hope this helps!
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