Question

please find radius of the circle

Answer 1

Answer:

13

Step-by-step explanation:

let radius of circle be r.

let PO=y

QO=17-y

acc to pythagoras theorem

$r = \sqrt{po {}^{2} + ap {}^{2} } \\ = \sqrt{po {}^{2} + 5 {}^{2} } \\ r ^{2} = po {}^{2} + 25 \\ also \: r {}^{2} = (17 - po) {}^{2} + 144$

$equating \: both \: eqns. \\ po {}^{2} + 25 = (17 - po) {}^{2} + 144 \\ po ^{2} + 25 = 289 - 34po + po {}^{2} + 144 \\ 25 =289 - 34po + 144 \\ po = 12 \\ r = \sqrt{po ^{2} + 5 {}^{2} } = \sqrt{12{}^{2} + 5 {}^{2} } = 13$