Math, asked by atmanmahapatrap30i0d, 1 year ago

please find the answer

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Answered by gaurav2013c
2
Let the side of cube be a
Volume of cube = a^3

Diameter of sphere = Side of cube =a
Radius of sphere = a/2

Volume of sphere = 4 pi *a^3 / 3 * 2*2*2
= pi *a^3 /6


Volume of cube :Volume of sphere = a^3 : pi a^3 /6
= a^3 *6 / pi *a^3
= 6/pi
= 6/(22/7)
= 6*7/22
= 42/22
= 21:11

Hope it will help you

Please mark as brainliest if you liked the solution

atmanmahapatrap30i0d: thanks a lot... tommorow is my exam......
Answered by mysticd
0
Hi ,

Let the length of the side

of the cube = a units

according to the problem given ,

diameter of the Sphere ( d ) = length of the side

of the cube

d = a

Let the radius of the Sphere ( r ) = d/2

r = a/2 units

volume of cube = V1 = a³ ----( 1 )

volume of the Sphere = V2 = ( 4/3 ) πr³

V2 = ( 4/3 ) ( 22/7 ) ( a/2 )³

= 11a³/21 ---( 2 )


required ratio = ( V1 )/( V2 )

= ( a³ ) / ( 11a³ / 21 )

= 21/11

= 21 : 11

I hope this helps you.

:)
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