please find the answer
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Let the side of cube be a
Volume of cube = a^3
Diameter of sphere = Side of cube =a
Radius of sphere = a/2
Volume of sphere = 4 pi *a^3 / 3 * 2*2*2
= pi *a^3 /6
Volume of cube :Volume of sphere = a^3 : pi a^3 /6
= a^3 *6 / pi *a^3
= 6/pi
= 6/(22/7)
= 6*7/22
= 42/22
= 21:11
Hope it will help you
Please mark as brainliest if you liked the solution
Volume of cube = a^3
Diameter of sphere = Side of cube =a
Radius of sphere = a/2
Volume of sphere = 4 pi *a^3 / 3 * 2*2*2
= pi *a^3 /6
Volume of cube :Volume of sphere = a^3 : pi a^3 /6
= a^3 *6 / pi *a^3
= 6/pi
= 6/(22/7)
= 6*7/22
= 42/22
= 21:11
Hope it will help you
Please mark as brainliest if you liked the solution
atmanmahapatrap30i0d:
thanks a lot... tommorow is my exam......
Answered by
0
Hi ,
Let the length of the side
of the cube = a units
according to the problem given ,
diameter of the Sphere ( d ) = length of the side
of the cube
d = a
Let the radius of the Sphere ( r ) = d/2
r = a/2 units
volume of cube = V1 = a³ ----( 1 )
volume of the Sphere = V2 = ( 4/3 ) πr³
V2 = ( 4/3 ) ( 22/7 ) ( a/2 )³
= 11a³/21 ---( 2 )
required ratio = ( V1 )/( V2 )
= ( a³ ) / ( 11a³ / 21 )
= 21/11
= 21 : 11
I hope this helps you.
:)
Let the length of the side
of the cube = a units
according to the problem given ,
diameter of the Sphere ( d ) = length of the side
of the cube
d = a
Let the radius of the Sphere ( r ) = d/2
r = a/2 units
volume of cube = V1 = a³ ----( 1 )
volume of the Sphere = V2 = ( 4/3 ) πr³
V2 = ( 4/3 ) ( 22/7 ) ( a/2 )³
= 11a³/21 ---( 2 )
required ratio = ( V1 )/( V2 )
= ( a³ ) / ( 11a³ / 21 )
= 21/11
= 21 : 11
I hope this helps you.
:)
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