Please find the answer
Attachments:
Answers
Answered by
2
area of trapezium =1/2×sum of parallel sides ×height.
let pq=x then,sr=x×2/3 =2x/3
==> 1/2×(x+2x/3)×5
==>1/2×(3x+2x/3)×5
==>1/2×5x/3×5
==>25x/6 its your answer .
mark as brainliest plz
let pq=x then,sr=x×2/3 =2x/3
==> 1/2×(x+2x/3)×5
==>1/2×(3x+2x/3)×5
==>1/2×5x/3×5
==>25x/6 its your answer .
mark as brainliest plz
Similar questions