Question

please find the answer​

Answer 1

FOR MULTIPLES OF 2:

A.P : 10,12,14,.........., 98

a=10,d=2 ,Tn=98

Tn=a+(n-1)d

98=10+(n-1)2

88=(n-1)2

44=n-1

45=n

Now,

Sn=n/2{2a+(n-1)d}

=45/2{2(10)+(45-1)2}

=45/2{20+(44)2}

=45/2{108}

=45×54

=2430

similarly we can find for multiples of three

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