please find the answer for this question
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Hi ,
( 0.000343 )^-3/2× ( 0.49 ) -3/2
= ( 343/100000 ) ^3/2 × ( 49/100 )^-3/2
= ( 1000000/343 ) ^2/3 ×(100/49)^3/2
= [ ( 100/7 )³ ]^2/3 × [ (10/7 )²]^3/2
= ( 100/7)^ 3/1 × 2/3 ×( 10/7 ) ^ 2/1 ×3/2
= ( 100/7 )² × ( 10/7 )³
= ( 100²× 10³) / ( 7² × 7³ )
= ( 10 )^5/ 7^5
= ( 10/7 ) ^5
= ( 1/ 0.7 )^5
= ( 0.7 ) ^ -5
I hope this helps you.
: )
( 0.000343 )^-3/2× ( 0.49 ) -3/2
= ( 343/100000 ) ^3/2 × ( 49/100 )^-3/2
= ( 1000000/343 ) ^2/3 ×(100/49)^3/2
= [ ( 100/7 )³ ]^2/3 × [ (10/7 )²]^3/2
= ( 100/7)^ 3/1 × 2/3 ×( 10/7 ) ^ 2/1 ×3/2
= ( 100/7 )² × ( 10/7 )³
= ( 100²× 10³) / ( 7² × 7³ )
= ( 10 )^5/ 7^5
= ( 10/7 ) ^5
= ( 1/ 0.7 )^5
= ( 0.7 ) ^ -5
I hope this helps you.
: )
dharshanapriyaa:
thanks for your answer
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