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Answer:
Option D
Explanation:
C₂H₅O⁻ in presence of C₂H₅OH acts as a strong base and follows E2 mechanism in which hydrogen antiperiplanar with respect to Bromine is abstracted/ eliminated by the base.
From the given fischer projection, we can see that since H is anti to the Br atom attached to adjacent carbon, we get an alkene by removing these two elements
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