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GIVEN :-
- The driver of a train A is moving at a speed of 30 m/s sights another train B moving on the same track towards his train at a speed of 10 m/s . He immediately applies brakes and achieve a uniform retardation of 4 m/s .
TO FIND :-
- The minimum distance between the trains to avoid head - on Collision.
SOLUTION :-
we have ,
- initial velocity , u = 30 m/s + 10 m/s = 40 m/s
- Final velocity , v = 0 m/s [ brakes applied ]
- Acceleration , a = -4 m/s² [ Retardation ]
★ By using third equation of motion ★
→ v² - u² = 2as
- v = final velocity.
- u = initial velocity.
- a = acceleration.
- s = distance covered.
→ (0)² - (40)² = 2 × (-4) × s
→ 0 - 1600 = -8s
→ -1600 = -8s
→ s = -1600/8
→ s = 200 m.
HenceThe minimum distance between the trains to avoid head - on Collision is 200 m.
Option (B) ✅
MisterIncredible:
Brilliant ^_^
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