Question

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Answer 1

Answer:

1. It is not true that this polynomial has no zero. In fact this polynomial has two zeros I and -i. the fact is that this polynomial has no zero in real numbers because there is no real value of x for which the value of the polynomial is zero.

2. (x-3)(x-2) = 0

x = 2,3

3. -a, a, -1, 1/2, -2

4. ans = 3x^2 + x + 1

5 quotient = 2x+1, remainder = 1

Answer 2

Step-by-step explanation:

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