Question

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Answer 1

Answer:

if n is a natural number it is a other than perfect square number then √n is IRRATIONAL number

Answer 2

Answer:

since n is not a perfect square therefore on solving root n we will get a number which would be non terminating and non repeating decimal expansion which would be irrational number

eg $\sqrt{2}$ , $\sqrt{3\\}$ etc

Step-by-step explanation:

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