Math, asked by agamkatariadps, 1 year ago

Please find the area of this hexagon

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shadowsabers03: Never mind BE! We can find it only by the side length!!!

shadowsabers03: The equation is 6root3 a^2 / 4, where a is side length.

agamkatariadps: i need some easy answer with two trapeziums

shadowsabers03: But it'll be of much longer steps. Applying the equation is easier.

Answers

Answered by shadowsabers03

There's no need of the length of BE! We can find it only by the side length!!!

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The equation to find the area of a regular hexagon of side length 'a' is,

$\frac{6\sqrt{3}a^2}{4}$

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Here, a = 6 cm.

Area = 54√3 cm²

$\frac{6\sqrt{3} \times 6^2}{4} \ = \ \frac{216\sqrt{3}}{4} \ = \ \bold{54\sqrt{3}}$

But, one minute. There's a contradiction.

The given figure is a regular hexagon. If the side length is 6 cm each, then the length of BE should be 18 cm.

But how BE can be 14 cm?!

If the side length of a regular hexagon is 'a', then the length of the diagonal like BE which connects the opposite points shall be '3a'.

So either BE shall be 18 cm if side length is 6 cm, or the side length shall be 14/3 cm if BE is 14.

So we can say that there isn't such a hexagon.

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Thank you. Have a nice day. :-))

#adithyasajeevan

Answered by mihirsthacker

Sorry,

But we need the length of the side to find it's area, I tried it but it's not possible even by construction of other segments.

Sorry for the inconvenience.

agamkatariadps: Its ok

shadowsabers03: Oh, this answer blew my mind. Good answer.

shadowsabers03: Edited my answer.

shadowsabers03: But mark this answer as the brainliest.

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