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HimadriShekhar:
angle DCB=angle DAB = 64 AC bisects angle DCB and angle DAB x= DCB. angle DCB + angle ABC =180 . 64 +ABC = 180 . ABC = 116 . y= 116÷2=58
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Answered by
1
x=23
y=58
hope it helps
y=58
hope it helps
Answered by
1
angle A is 64degree
angle C =angle A
therefore 64=64
angle x = half of angle C
x= 32 degrees
angle C+ angle B =180 ( linear pair of angles)
let angle B be x
64+x=180
x=180-64
x=116
therefore half of angle B=y
y=116/2
y=58 degrees...
angle C =angle A
therefore 64=64
angle x = half of angle C
x= 32 degrees
angle C+ angle B =180 ( linear pair of angles)
let angle B be x
64+x=180
x=180-64
x=116
therefore half of angle B=y
y=116/2
y=58 degrees...
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