please find the attached question ..
it's urgent
find the value of x in the given question
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Let 2^x=y
2^(1-x)=2/2^x=2/y
2^x+2^(1-x)=y+2/y=3
y^2+2=3y
y^2-3y+2=0
solving it, we get
y=2 or 1
2^x=2 or 1
x=1 or 0
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