Math, asked by sgurtaj25, 8 months ago

please find the derivative
fast

Attachments:

Answers

Answered by aryamewada05
0

Step-by-step explanation:

cos^2x.tan^3(5x)

dy/dx= cos^2x.d/dx[ tan^3(5x)] + tan^3(5x). d/dx( cos^2x)

= cos^2x. 3sec^4(5x).d/dx(5x) + tan^3(5x).(-2sinx)

=cos^2x. 3sec^4(5x).5 + tan^3(5x).(-2sinx)

=5.cos^2x. 3sec^4(5x) - tan^3(5x).(2sinx)

Attachments:
Answered by Rohit18Bhadauria
0

\rule{300}{2}

\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}

See this attachment

This is the best possible answer

\large{\boxed{\mathbf\pink{\fcolorbox{red}{yellow}{Hope\:you\:have}}}}

\large{\boxed{\mathbf\pink{\fcolorbox{red}{yellow}{Understood}}}}

<marquee>♥️Please mark it as♥️</marquee>

\huge\underline\mathcal\red{Brainliest}

</p><p>\huge{\boxed{\mathbb\green{\fcolorbox{red}{blue}{Thank\:You}}}}

\rule{300}{2}

Attachments:
Similar questions