Question

please find the distance for the above points​

Answer 1

Answer:

√a⁴-a⁴sin²2x/2 assume x=thetha

Answer 2

Answer:

distance=a

Step-by-step explanation:

distance between two points=

√(x2-x1)^2+(y2-y1)^2

x1=0,y1=0

x2=a^2cos^(2)0

y2=a^2sin^(2)0

distance=√(a^2cos^(2)0)^2+(a^2sin^(2)0)^2

=>[√a^4(cos^(4)0+sin^(4)0)]

=>[√a^4(1-2sin^(2)0cos^(2)0)]

=>[(√a^(4))-((a^4sin^(2)20)\2)]

0 is theta

i hope its helpful mark me as branliest if its correct