Question

please find the factor of ​

Answer 1

Answer:

We will use the quadratic method to solve this question.

b^2-4ac = 18-16 = 2

Hence. it will have 2 values for x

value:-

1. $\frac{-3\sqrt{2} +\sqrt{2}}{2}$

2. $\frac{-3\sqrt{2} -\sqrt{2}}{2}$

Solve and find the answer.

Hope this helps.

Please mark as brainliest.

Answer 2

Answer:

Step-by-step explanation:

x^2+root3x+4=0

X^2+(2root2+root2)x+4=0

X^2+(2root2)x +root2x + 4=0

X(x+2root2) + root2(x+2root2)=0

Factors:-(X+root2) (x+2root2)=0

Zeroes:-If..x+root2=0 x=(-root2) If...x+2root2=0

X=(-2root2)