Question

Please find the HCF using euclids division lemma. ​

Answer 1

Given :-

i) 420,130

ii) 616,32

iii)60,84

To find :-

The H.C.F of given numbers by Euclid division lemma

• Euclid division lemma =a=bq+r

A.T.Q :-

i) 420,130

=> 420=130×3+30

=> 130= 30×4+10

=> 30= 10×3+0

So the H.C.F of 420 ,130 is 10

ii) 616,32

=> 616=32×19+8

=> 32= 8×4+0

So the H.C.F of 616 ,32 = 8

iii) 60,84

=> 84= 60×1+24

=> 60=24×2+12

=> 24=12×2+0

So the H.C.F =12

Thus The H.C.F of these numbers is

=> 10 ,8 and 12

Answer 2

Answer:

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