Question

please find the median​

Answer 1

Answer:

{(n + 1) ÷ 2}th value

apply this formula for finding median

the question is not do clearly seen

Answer 2

Table :-

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$\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}\cline{1-10}\sf {{\:\:\:marks\:\:\:}} &\sf {{0-10}}&\sf {{10-20}}&\sf {{20-30}}&\sf {{30-40}}&\sf {{40-50}}&\sf {{50-60}}&\sf {{60-70}}&\sf {{70-80}}&\sf {{80-90}}\\\cline{1-10}\sf Frequency &\sf 3 &\sf 5&\sf 16&\sf 12&\sf 13&\sf 20&\sf 5&\sf 4&\sf 1\\\cline{1-10}\end{tabular}$

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Solution :-

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First let us construct the frequency table :-

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$\begin{tabular}{|c|c|c|}\cline{1-3}\sf Marks ( x ) &\sf Number\: of\: students ( f )&\sf Cumulative \: frequency (c.f.) \\\cline{1-3}\sf 0 - 10 &\sf 3&\sf 3 \\\ \sf 10 - 20 &\sf 5 &\sf 8 \\\ \sf 20 - 30 &\sf 16 &\sf 24 \\\ \sf 30 - 40 &\sf 12&\sf 36 \\\ \sf 40 - 50 &\sf 13&\sf 49 \\\ \sf 50 - 60 &\sf 20 &\sf 69 \\\ \sf 60 - 70 &\sf 5&\sf 74 \\\ \sf 70 - 80 &\sf 4&\sf 78 \\\ \sf 80 - 90 &\sf 1&\sf 79\\\cline{1-3}&\sf 79 \\\cline{1-2}\end{tabular}$

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Clearly ; total number of students = 79

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i.e. n = 79 ; which is odd

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therefore ;

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$\sf{\bigstar{\large{\boxed{\purple{\bold{ Median = \bigg\lgroup\dfrac{ n + 1 }{2}\bigg\rgroup^{th} term }}}}}}$

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$\sf\implies Median = \bigg\lgroup\dfrac{79 + 1}{2} \bigg\rgroup ^{th} term$

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$\sf\implies Median = \bigg\lgroup\dfrac{80}{2} \bigg\rgroup ^{th} term$

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$\sf\implies Median = 40^{th} term$

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$\sf\implies Median = marks\: of \: 40th \: children$

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Acc. to the table obtained above , it can be observed that the marks from 37th child to 49th child is 13

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Therefore ;

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Marks of 40th child = 13

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Median weight = 13

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