Question

please find the solution of this question with proper explanation ​

Answer 1

GiveN :

• Angle be 30°.
• Sides right angle is AB , BC and CD.
• AB = 5 cm.

To FinD :

The sides of AC and BC.

SolutioN :

Let,

• Angle be θ.

So, For Sides AC

$\tt \dagger \: \: \: \: \: sin\, \theta = \dfrac{Perpendicular}{Hypotenuse}$

$\tt \mapsto sin\, 30 = \dfrac{5}{AC}$

$\tt \mapsto \dfrac{1}{2} = \dfrac{5}{AC}$

$\tt \mapsto AC = 10 cm.$

$\rule{90}2$

For Side BC

$\tt \dagger \: \: \: \: \: tan \,\theta = \dfrac{Perpendicular}{Base}$

$\tt \mapsto tan \,30 = \dfrac{5}{BC}$

$\tt \mapsto \dfrac{1}{ \sqrt{3} } = \dfrac{5}{BC}$

$\tt \mapsto BC = 5 \sqrt{3} cm$

$\rule{200}3$

MorE InformatioN :

• Sin 30 = 1 / 2
• tan 30 = 1 /√3.