Question

please find the total distance and its maximum speed attained​

Answer 1

Answer:

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Answer 2

a=2m per second square

u=0

t=1.5

we have to find final velocity when train starts

v=u+at

v=0+2×1.5

v=3mpersecond

we have to find distance when train starts =

s=ut+1/2at^2

s=0×1.5+1/2×2×1.5×1.5

s=2×2.25

s=4.5km

distance travelled by train when it applies brake

s=3×60+1/2×2×60×60

s=3780

total distance travelled=4500+3780=8280m

and the maximum speed is

0+3+0+3=9mlsecond