Question

Please find the value of x √2(√2x+1)=3x-4-3√2​

Answer 1

Answer:

x= 4(1+root2)

Step-by-step explanation:

2x+root2 = 3x-4-3root2

x-4-4root2=0

x=4(1+root2)

correct me if i am wrong

THANK YOU

Answer 2

Step-by-step explanation:

(3x)^(1/8) = (2x)^(1/4)

Taking 8th power on both sides.

3x = 4x^2

4x^2-3x = 0.

x(4x-3) = 0.

x = 0 or 3/4.