Question

please find the value of x​

Answer 1

Answer:

this is the solution

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Answer 2

$\huge{\dag}\:{\underline{\boxed{\sf{\purple{ᴀɴsᴡᴇʀ}}}}}$

ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ-:

➜$\frac{1}{3}$× $^3$ $\frac{1}{3}$$^-~^6$=$\frac{1}{3}$$^2~^x~^-~^1$

➜$\frac{1}{3}$$^3~^+~^(~^-~^6~^)$=$\frac{1}{3}$$^2~^x~^-~^1$

➜$\frac{1}{3}$$^-~^3$=$\frac{1}{3}$$^2~^x~^-~^1$

➜$\frac{1}{3}$$^-~^3~^-~^1$=$\frac{1}{3}$$^2~^x$

➜$\frac{1}{3}$$^-~^2$=$\frac{1}{3}$$^2~^x$

➜$\frac{1}{3}$$^-~^1$=$\frac{1}{3}$$^x$

Hence, -1 = x

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