Question

Please find the value of x

Answer 1

Hi!

since angle QTR = 90°
angle QTP = 180° - 90° = 90° [ Linear pair ]

let PS and QT intersect at O
therefore,
angle POT + angle OTP + angle TOP = 180°
[ angle sum property ]

angle POT + 90° + 30° = 180°
=> angle POT = 180° - 120° = 60°

angle POT = angle QOS [ vertically opposite angles)
=> angle QOS = 60°

In ∆QOS, using angle sum property of a triangle,

angle OQS + x + angle QOS = 180°
48° + x + 60° = 180°
=> x = 180° - 108° = 72°

therefore,
the value of x is 72°

Answer 2

I think it is correct answer