please find the value of x i can mark him as brainiest
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1- tan^2 60°/1+tan^2 60°= cos x
1 - (√3)^2/ 1+ (√3) = cos x
1-3/1+3 = cos x
-2/4=cos x
-1/-2= cos x
1 = 2cos x
2cos x = 1
Cos x=-1/2= 60°
1 - (√3)^2/ 1+ (√3) = cos x
1-3/1+3 = cos x
-2/4=cos x
-1/-2= cos x
1 = 2cos x
2cos x = 1
Cos x=-1/2= 60°
Urvish19:
thank you but the ans is 120
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