Question

please find the zeroes of polynomial 4x^2-5x-1

Answer 1

Hey!!!

Good Morning

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We have

=> 4x² - 5x + 1 = 0

By middle term splitting method

=> 4x² - 4x - x + 1 = 0

=> 4x(x - 1) - (x - 1) = 0

=> (4x - 1)(x - 1) = 0

Thus x = 1 or x = 1/4

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Answer 2

Hey here is your answer
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$let \: . \\ 4 {x}^{2} - 5x + 1 = 0 \\ \\ 4 {x}^{2} -4x - x + 1 = 0 \\ \\ 4x(x - 1) - 1(x - 1) = 0 \\ \\ (4x - 1)(x - 1) = 0 \\ \\ (4x - 1) = 0 \: \: \: and \: \: \: (x - 1) = 0 \\ \\ 4x = 1 \: \: \: and \: \: \: x = 1 \\ \\ x = \frac{1}{4} \: and \: 1 \: are \: zeroes \: of \: polynomial$
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