Question

please find this answer​

Answer 1

Answer:

(5) 169.6 m³ & (6) 80 m³

Step-by-step explanation:

(5)

Water expands by 6% of its volume as it freezes.

The volume of water = 160 m³

Volume of ice that can be obtained = 160 + 6% of 160

$= 160 + \frac{6 \times 160}{100} \\ = 160 + \frac{96}{10} \\ = 160 + 9.6 \\ = 169.6 \: {m}^{3}$

(6)

Water expands by 2% of its volume.

Volume of ice = 81.6 m³

Let volume of water that is required be x.

Volume of ice = x + 2% of x

=> 81.6 = x + 2% of x

$= > 81.6 = x + \frac{2 \times x}{100} \\ = > 81.6 = \frac{x}{1} + \frac{2x}{100} \\ = > 81.6 = \frac{100x + 2x}{100} \\ = > 81.6 \times 100 = 102x \\ = > x = \frac{8160}{102} \\ \: \: \: \: \: \: \: \: \: \: \: x = 80 \: {m}^{3}$