Question

please find this question

Answer 1

Answer:

hope it helps...

Step-by-step explanation:

a)$(2x-1)^{3} =(2x-1)(2x-1)(2x-1)$

=(4x^2-4x+1)(2x-1)

=8x^3-12x^2+6x-1

coefficient of x^4=0

coefficient of x^3=8

coefficient of x^2=-12

coefficient of x=6

b)(2x+3,3y-7)=(3x+1,y+3)

equating the x and y values...

2x+3=3x+1    ⇒ x=2

3y-7=y+3      ⇒ y=5.

:)