Question

Please find this question with the method

Answer 1

Answer:

hi ZARA

Step-by-step explanation:

10/a + 6/b =8 ⇒(10b + 6a)/ab = 8

⇒ 10b+6a=8ab (equation 1)

6/a + 10/b =4 ⇒(6b+ 10a)/ab = 4

⇒6b+10a=4ab(equation 2)

mutiplying equation 2 with 2

we get 12b+20a=8b (let this be equation 3)

dividing equation 3 by equation 1

we get (12b+20a)/(10b+6a) = 8b/8b

(12b+20a)/(10b+6a) =1 ⇒ 12b+20a=10b+6a

2b = -14a ⇒ b= -7a

substituting the value of b in (equation 1)

10×(-7a) + 6a = 8×a×(-7a)

-70a + 6a = -56a² ⇒ -64a= -56a² ⇒ a/a² = -56/-64

1/a = 7/8

now ,we can write b=-7a as a= -b/7

so,substituting the value of a in (equation 1)

we get, 10b + 6×(-b/7) = 8×(-b/7)×b

10b+ (-6b/7) = -8b²/7

10b -6b/7 = -8b²/7

(70b-6b)/7 = -8b²/7

cancelling the denominator in both sides as they are same

70b-6b = -8b² ⇒ 64b = -8b² ⇒ b/b² = -8/64 ⇒ 1/b= -1/8

so, 1/b=-1/8

so 1/a - 1/b = 7/8 - (-1/8) = 7/8 + 1/8 = 8/8 = 1

Hope this helps you

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