Please find x,y,z where ECD=24,CDE=42
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CED=180-66=114. (ASP)
AEC+CED=180. (linear pair)
AEC=66
IN TRI. AEC
y=AEC. (angles opp to equal sides)
y=66
z+y+AEC=180. (ASP)
z+2y=180
z=180-132
z=48
also x=42. (alternate interior angles)
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AEC+CED=180. (linear pair)
AEC=66
IN TRI. AEC
y=AEC. (angles opp to equal sides)
y=66
z+y+AEC=180. (ASP)
z+2y=180
z=180-132
z=48
also x=42. (alternate interior angles)
****************************************************
Hope u understand my words i need only few brainliest for the next rank. If i was helpful then pl pl pl mark me as brainliest
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