please first solve part 1 then you will understand 2nd part.
I)find the sqrt of i+1 .
II)and why in it the value of a²=b².
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i) The square root of 1 - i is shown here; With i(subscript 2) meaning, i to the second degree of imaginary expansion. (1-i)^2=1^2+i^2–(2*1*I). Thus square root of (1-i) is √[(1-√i)(1+√i)].
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