Question

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class 10th​
Chapter 3
Exercise 3.3 no 3

Answer 1

Answer:

(i) Ans

13 and 39 are the two numbers where the difference between them is 26 and one number is 3 times the other number.

Given:

The difference between two numbers is 26 and one number is three times the other number.

To find:

Two numbers = ?

Solution:

Given, the difference between two numbers is 26.

So, let us take one of the number to be x.

Thus, the other number is = 26 + x=26+x

Also, given, one number is three times the other number, i.e.

3x = (26 – x)3x=(26–x)

3x - x = 263x−x =26

2x = 262x=26

x = 26 2x =

2

26

x = 13.x=13.

So, one of the number is = 13.=13.

Thus, the other number is = 26 + 13 = 39=26+13=39

Hence, the two numbers are 13 and 39. Ans

(ii) Ans

Let larger angle be x

Smaller angle be y

Given that

Larger angle exceeds smaller angle 18 degree

x-y= 18

Also both angle is supplementary

Sum of both angle = 180 degree Ans

(iii) Ans

Let coast of one bats = Rs .x

Coast of one ball =Rs .y

Given that

coach buys 7 bats and 6 balls for Rs .3800

7 ×(cost of one bat)+6×(cost of one ball)=3800

7x +6y= 3800 Ans

Hope it help to you