Question

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Answer 1

$( \frac{1}{6} + \frac{2}{3} ) \div ( - { \frac{3}{5} }^{7 - 5} ) \\ \\ \frac{5}{6} \div { (\frac{ - 3}{5} })^{2} \\ \\ \frac{5}{9} \times \frac{25}{9} \\ \\ = \frac{125}{81}$

Answer 2

Step-by-step explanation:

$({6}^{ - 1} + (\frac{3}{2} )^{ - 1} ) \div (\frac{-3}{5} ^{7} \times ( \frac{ - 3}{5} ) ^{ - 5} )$

Any expression raised to the power of -1 equals its reciprocal

$( \frac{1}{6} + \frac{2}{3} ) \div (( \frac{ - 3}{5} ^{7} \times {( \frac{ - 3}{5} })^{ - 5}$

Calculate the product

$( \frac{1}{6} + \frac{2}{3} ) \div ( \frac{ - 3}{5})^{2}$

Add the fractions

$\frac{5}{6} \div ( \frac{ - 3}{5}) ^{2}$

To raise a fraction to a power raise the numberator and denominator to that power

$\frac{5}{6} \div \frac{9}{25}$

To divide by a fraction , multiply by the reciprocal of that fraction

$\frac{5}{6} \times \frac{25}{9}$

Multiply the fractions

Solution :

$\frac{125}{54}$

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