please friend slove these!!
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arya641:
nope
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Use this:
BODMAS
B=Bracket
O=Of
D=Division
M=Multiply
A=Addition
S=Subtract
This means,
First solve the inner brackets then 'of' refers to multiplication then division then add and finally subtract.
If anyone is missing then jump to other form,
like if there is no division then jump to multiplication.
Example:
Q. 2 of [24÷4{3×2 of 2+3}]
Ans. 2 of [24÷4{3×2×2+3}] ..........( i converted 'of' in multiplication and now i am solving inner bracket)
2 of [24÷4{12+3}
2 of [24÷4{15}]
2 of [24÷4×15].............(If there is no symbol then there will sign of multiplication)
2 of [6×15].........( now i divided)
2 of [90]..........( Bracket solved)
2×90...........('of' changed into multiplication)
180
FOLLOW THIS RULE AND SOLVE ABOVE QUESTIONS.
(I do not solved beacuse it will take so much time)
HOPE IT HELPS YOU!
BODMAS
B=Bracket
O=Of
D=Division
M=Multiply
A=Addition
S=Subtract
This means,
First solve the inner brackets then 'of' refers to multiplication then division then add and finally subtract.
If anyone is missing then jump to other form,
like if there is no division then jump to multiplication.
Example:
Q. 2 of [24÷4{3×2 of 2+3}]
Ans. 2 of [24÷4{3×2×2+3}] ..........( i converted 'of' in multiplication and now i am solving inner bracket)
2 of [24÷4{12+3}
2 of [24÷4{15}]
2 of [24÷4×15].............(If there is no symbol then there will sign of multiplication)
2 of [6×15].........( now i divided)
2 of [90]..........( Bracket solved)
2×90...........('of' changed into multiplication)
180
FOLLOW THIS RULE AND SOLVE ABOVE QUESTIONS.
(I do not solved beacuse it will take so much time)
HOPE IT HELPS YOU!
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