please friends answer this as fast as possible........
two angles are complementary. The larger angle is 3 degree less than twice the measure of smaller angle. find the measure of each angle ?
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Answered by
2
let the larger angle be x and smaller angle be y
larger angle=2y-3
according to the given condition,
x+y=90
2y-3+y=90 ( since x=2y-3)
3y-3=90
3y=93
y=93/3
y=31
so smaller angle y = 31degrees
larger angle = 2*31-3=59
so 59+31=91
larger angle=2y-3
according to the given condition,
x+y=90
2y-3+y=90 ( since x=2y-3)
3y-3=90
3y=93
y=93/3
y=31
so smaller angle y = 31degrees
larger angle = 2*31-3=59
so 59+31=91
Answered by
1
Let the first angle be x°
So second angle = (2x - 3)°
So, since they are complementary -
x + 2x - 3° = 90°
3x = 93°
x = 31°
So, fist angle = x = 31°
Second angle = (2x - 3)° = 59°
So second angle = (2x - 3)°
So, since they are complementary -
x + 2x - 3° = 90°
3x = 93°
x = 31°
So, fist angle = x = 31°
Second angle = (2x - 3)° = 59°
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