Question

please!! friends answer this question

Answer 1

Hey dear!!


Here is yr answer......

$given \\ f(x) = {3x}^{4} + {2x}^{3} - \frac{ {x}^{2} }{3} - \frac{x}{9} + \frac{2}{27} \\ \\ g(x) = x + \frac{2}{3 } \\ x + \frac{2}{3} = 0 \\ x = - \frac{2}{3} \\ \\ f( - \frac{2}{3} ) = 3( - \frac{2}{3} )^{4} + 2( - \frac{2}{3} )^{3} - \frac{ { (- 2})^{2} }{3} - (\frac{ - 2}{9} ) + \frac{2}{27} \\ \\ f( - \frac{2}{3} ) = 3( \frac{16}{81} ) + 2( - \frac{8}{27} ) - \frac{4}{3} + \frac{2}{9} + \frac{2}{27} \\ \\ f( - \frac{2}{3} ) = \frac{16}{27} - \frac{16}{27} - \frac{4}{3} + \frac{2}{9} + \frac{2}{27} \\ \\ f( - \frac{2}{3} ) = \frac{16 - 16 - 36 + 6 + 2}{27} \\ \\ f( - \frac{2}{3} ) = \frac{24 - 52}{27} \\ \\ f( - \frac{2}{3} ) = \frac{ - 28}{27}$

So, the remainder is -28/27.


Hope it hlpz....

Answer 2

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