please friends give me this question answer plase
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Answer:
cos^(-1)[(n^(2)-1)/(n^(2)+1)]
Explanation:
|A+B|=n|A-B
=> (A^(2)+B^(2)+2AB cos theta) = n^(2)(A^(2)+B^(2)-2ABcos theta)
it is given that A+B
hence cos theta = (n^(2)-1)/(n^(2)+1)
so theta is cos^(-1)[(n^(2)-1)/(n^(2)+1)]
Hope it helps...
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