Question

please friends give me this question answer plase​

Answer 1

Answer:

cos^(-1)[(n^(2)-1)/(n^(2)+1)]

Explanation:

|A+B|=n|A-B

=> (A^(2)+B^(2)+2AB cos theta) = n^(2)(A^(2)+B^(2)-2ABcos theta)

it is given that A+B

hence cos theta = (n^(2)-1)/(n^(2)+1)

so theta is cos^(-1)[(n^(2)-1)/(n^(2)+1)]

Hope it helps...