Question

please friends help me​

Answer 1

Step-by-step explanation:

kx²- Kx + 1 = 0

for equal roots, b² - 4ac = 0

a = k, b = - k and c = 1

(-k)² - 4×k×1 = 0

=> k² - 4k = 0

=> k(k - 4) = 0

=> k = 0 and k = 4 Answer

Answer 2

Answer:

k = 0

Step-by-step explanation:

Given that the equation has equal roots

Hence, Δ = 0

kx²-kx+1 = 0

Here,

a = k

b = -k

c = 1

Δ = 0

b²-4ac = 0

(-k)² - 4(k)(1) = 0

k - 4k = 0

-3k = 0

∴k = 0

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