Question

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Please friends help me.....
CD is a diameter which meets the chord AB in E,such that AE=BE=4cm.If CE is 3cm, find radius of circle.
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Answer 1

Step-by-step explanation:

We have: .OA=OD=R . and: .OE=R−3

In right triangle OEA:(R−3)^2+4^2=R^2⇒R^2−6R+9+16=R^2

Therefore: .6R=25⇒R=25/6

Answer 2

Heya

Ans;✍️✍️✍️✍️✍️

Given,

CD is a diameter which meets the chord a b in E .

AE = BE = 4cm

CE = 3cm

And

The and is 7

Thank you