Question

please friends I asked soo many persons but noo body is answering please give explanation please​

Answer 1

There is no value of m for which $\dfrac{2m-1}{2+m}=2$

Given:

$\dfrac{2m-1}{2+m}=2$

To Find:

Solve for m

Solution:

$\dfrac{2m-1}{2+m}=2$

Step 1 :

Substract 2 from both sides and simplify

$\dfrac{2m-1}{2+m} - 2=2 - 2\\ \\\dfrac{2m-1 -4 - 2m}{2+m} =0\\\\\\\dfrac{-5}{2+m} =0$

 Step 2 :

Note that RHS = 0  but LHS can not be zero

Hence there does not exist any solution

There is no value of m for which $\dfrac{2m-1}{2+m}=2$

Another way

$\dfrac{2m-1}{2+m}=2$

Transpose 2 + m

2m - 1 = 4 + 2m

=> - 1 = 4     ( cancel 2m from both side)

This is absurd as -1 ≠ 4

Hence no solution exist,

There is no value of m for which $\dfrac{2m-1}{2+m}=2$