Question

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Answer 1

let the no.be x and x plus 2
${(x + 2)}^{2} = {x}^{2} + 36 \\ {x}^{2} + 4 + 4x = {x}^{2} + 36 \\ 4 + 4x = 36 \\ 4x = 32 \\ x = 8$
the numbers are 8 and 10 respectively.

Answer 2

Let the two consecutive even nos be x and x+2
Now,(x+2)^2 - x^2= 36
x^2+4x+4 - x^2 = 36
4x + 4 = 36
4x = 32
So,x = 8 and x+2 = 10
Thus,the nos are 8 and 10.